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OT: Specific Gravity vs. % Stammwürze

Posted by Nick B. on 2015-09-07 07:31:04

Some readers might not be aware of what your numbers mean. They represent original specific gravity, post-boil, pre-fermentation. They can be roughly converted to % Stammwürze or ° Plato by subtracting 1000 and dividing by 4. Thus, 1038 OG => 38 / 4 = 9.5 % Stammwürze.

Followups:

OT: Specific Gravity vs. % Stammwürze by barry on  2015-09-07 12:31:35

OT: Specific Gravity vs. % Stammwürze by Nick B. on  2015-09-08 00:45:00

OT: Specific Gravity vs. % Stammwürze by barry on  2015-09-08 01:23:58